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10 questions from this quiz
Quadratic
sin2θ+cos2θ=1\sin^2 \theta + \cos^2 \theta = 1sin2θ+cos2θ=1
θ=θ0+180∘n\theta = \theta_0 + 180^\circ nθ=θ0+180∘n
2sinθcosθ2\sin \theta \cos \theta2sinθcosθ
0∘0^\circ0∘ to 360∘360^\circ360∘
30∘,90∘,150∘30^\circ, 90^\circ, 150^\circ30∘,90∘,150∘
An angle more complicated than just θ\thetaθ
0≤3θ≤5400 \leq 3\theta \leq 5400≤3θ≤540
θ0\theta_0θ0 and 180∘−θ0180^\circ - \theta_0180∘−θ0
To ensure they satisfy the original eqn
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