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10 questions from this quiz
All values within the domain
The more complex side
1+tan2θ=sec2θ1 + \tan^2 \theta = \sec^2 \theta1+tan2θ=sec2θ
secθ=1cosθ\sec \theta = \frac{1}{\cos \theta}secθ=cosθ1
tanθ=sinθcosθ\tan \theta = \frac{\sin \theta}{\cos \theta}tanθ=cosθsinθ
sin2θ=2sinθcosθ\sin 2\theta = 2\sin \theta \cos \thetasin2θ=2sinθcosθ
csc2θ=1+cot2θ\csc^2 \theta = 1 + \cot^2 \thetacsc2θ=1+cot2θ
Converting to sine and cosine
LHS = RHS
sec2θ=1+tan2θ\sec^2 \theta = 1 + \tan^2 \thetasec2θ=1+tan2θ
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