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11 questions from this quiz
Energy to heat 1 kg by 1°C
4200 J/kg°C
ΔE=mcΔθ\Delta E = mc\Delta\thetaΔE=mcΔθ
Change in thermal energy in joules
Water
J/kg°C
90,000 J
60°C
To reduce energy loss to surroundings
c=ΔEm×Δθc = \frac{\Delta E}{m \times \Delta\theta}c=m×ΔθΔE
It has a high specific heat capacity
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