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12 questions from this quiz
pd of primarypd of secondary\frac{\text{pd of primary}}{\text{pd of secondary}}pd of secondarypd of primary
Power in each coil is the same
Vp×Ip=Vs×IsV_p \times I_p = V_s \times I_sVp×Ip=Vs×Is
25,000 V
400,000 V
16
Reduced by factor of 16
power=pd×current\text{power} = \text{pd} \times \text{current}power=pd×current
power=current2×resistance\text{power} = \text{current}^2 \times \text{resistance}power=current2×resistance
256
Less energy dissipated as heat
Energy transferred more efficiently
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