The Formulae (Leaving Cert Mathematics): Flashcards

$\text{length} \times \text{width}$

$\frac{1}{2} \times \text{base} \times \text{height}$

$\pi r^2$ where $r$ is the radius

$\text{base} \times \text{height}$

$\frac{1}{2}(b_1 + b_2) \times h$

$\frac{\theta}{360^\circ} \times \pi r^2$ where $\theta$ is the angle in degrees

$\text{length} \times \text{width} \times \text{height}$

$\pi r^2 h$ where $h$ is the height

$\frac{4}{3} \pi r^3$

$\frac{1}{3} \pi r^2 h$

$\text{Area of Base} \times \text{height}$

$\frac{1}{3} \times \text{Base Area} \times \text{height}$