See what we can offer to your school
"SimpleStudy just makes sense...”
Get the best plan for your school
15 cards from this deck
Energy lost by one coulomb between two points in a circuit
Joule per coulomb (J C−1\text{J C}^{-1}J C−1) or volt (V)
Electrical potential energy converts to heat energy
V=WqV = \frac{W}{q}V=qW
Rate at which work is done or energy converts
Watt (W); 1 watt = 1 joule per second
P=VIP = VIP=VI
Total voltage = sum of individual voltages; V=V1+V2+V3V = V_1 + V_2 + V_3V=V1+V2+V3
All components experience the same voltage; V=V1=V2=V3V = V_1 = V_2 = V_3V=V1=V2=V3
In parallel with the component being measured
Electrical energy given to each coulomb by a source
Volt (V)
Sum of individual emfs; emf=emf1+emf2+emf3\text{emf} = \text{emf}_1 + \text{emf}_2 + \text{emf}_3emf=emf1+emf2+emf3
Voltage
One joule per coulomb
Select your subjects, and get access to A+ resources today.