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12 questions from this quiz
Energy lost by one coulomb
Joule per coulomb (J C−1\text{J C}^{-1}J C−1)
Converts to heat energy
4 V
460 W
They add up: V=V1+V2+V3V = V_1 + V_2 + V_3V=V1+V2+V3
Same across all: V=V1=V2V = V_1 = V_2V=V1=V2
In parallel with component
Energy given to each coulomb
No, it's a voltage
12 V
4.5 V
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