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12 questions from this quiz
The rate of doing work
P=WtP = \frac{W}{t}P=tW
1 joule per second
James Watt
147 W
7-10 watts
How well input converts to useful output
Useful OutputInput×100\frac{\text{Useful Output}}{\text{Input}} \times 100InputUseful Output×100
5%
42.9%
31.5 kW
70%
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