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10 questions from this quiz
DE∥BCDE \parallel BCDE∥BC and DE=12BCDE = \frac{1}{2}BCDE=21BC
12 units
Any triangle type
Line thru mid-point || to 2nd side bisects 3rd
Congruent triangles and parallelograms
SAS (Side-Angle-Side)
BD=CFBD = CFBD=CF and BD∥CFBD \parallel CFBD∥CF
1:2
Computer graphics for triangle subdivision
BCBCBC
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