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10 questions from this quiz
Angle between line of sight & horizontal
Angle looking down from horizontal plane
oppositehypotenuse\frac{\text{opposite}}{\text{hypotenuse}}hypotenuseopposite
oppositeadjacent\frac{\text{opposite}}{\text{adjacent}}adjacentopposite
They are equal
cosθ=adjacenthypotenuse\cos θ = \frac{\text{adjacent}}{\text{hypotenuse}}cosθ=hypotenuseadjacent
Angles of inclination (elevation)
Tangent
Draw a clear diagram
1 decimal place
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