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10 questions from this quiz
y=ab(x+p)+qy = ab^{(x+p)} + qy=ab(x+p)+q
b>0b > 0b>0 and b≠1b \neq 1b=1
The horizontal asymptote at y=qy = qy=q
The function is increasing
Exponential growth
Left by ppp units
All real numbers
{y:y<q,y∈R}\{y : y < q, y \in \mathbb{R}\}{y:y<q,y∈R}
Substitute x=0x = 0x=0 into the function
Shifts down 3 units; asymptote at y=−3y = -3y=−3
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