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273 K (0°C) and 101.3 kPa
22.4 dm³
Vg=22.4ngV_g = 22.4n_gVg=22.4ng
VA=abVBV_A = \frac{a}{b}V_BVA=baVB
Number in front of substance in balanced equation
Moles of solute per litre of solvent (mol·dm⁻³)
C=nVC = \frac{n}{V}C=Vn
Solution with precisely known concentration
CAVAa=CBVBb\frac{C_A V_A}{a} = \frac{C_B V_B}{b}aCAVA=bCBVB
Divide by 1000
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