The Trajectory of a Projectile (HSC SSCE Physics): Flashcards

Parabolic

When vertical velocity = 0

Only $u_y$ and launch height $y_0$

$h = y_0 - \frac{u_y^2}{2g}$

$t_{\text{flight}} = -\frac{2u_y}{g}$

Remains constant throughout

$x_{\text{max}} = u_x t_{\text{flight}}$

45°

Total time from launch to ground landing

Total horizontal distance projectile travels