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10 questions from this quiz
F=GMmr2F = \frac{GMm}{r^2}F=r2GMm
6.67×10−116.67 \times 10^{-11}6.67×10−11 N kg−2^{-2}−2 m2^22
It becomes one-quarter as strong
It is always attractive
Equal magnitude, opposite direction
Force per unit mass
N kg−1^{-1}−1 or m s−2^{-2}−2
9.89.89.8 m s−2^{-2}−2
Distance from centre of object
For small altitude changes
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