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10 cards from this deck
Thin metal coating applied via electrolysis
Negative electrode where reduction occurs
Positive electrode where oxidation occurs
Q=I×tQ = I \times tQ=I×t
96500 C mol−1^{-1}−1
Mass at electrode is proportional to charge passed
1 mole needs whole number of electron moles
Q=n(e−)×FQ = n(e^-) \times FQ=n(e−)×F
REDuction at CAThode
ANode OXidation
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