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10 cards from this deck
F=nIlBF = nIlBF=nIlB
When perpendicular to the magnetic field
Determines direction of force on current-carrying wire
Reverses current every half rotation
τ=rF\tau = rFτ=rF
F=qvBF = qvBF=qvB
Circular
r=mvqBr = \frac{mv}{qB}r=qBmv
Electric accelerates; magnetic directs
v=EBv = \frac{E}{B}v=BE
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