Reacting Volumes (AQA A-Level Chemistry): Flashcards

📚Flashcards
Reacting Volumes
Sign up to keep revising.Create a free account to study more flashcards and track your progress.

Practise the cards

10 cards from this deck

Show

Volume of 1 mole of gas at RTP

24 dm³

Formula: Volume of gas at RTP

Volume=moles×24 dm3\text{Volume} = \text{moles} \times 24 \, \text{dm}^3

Universality of 1 mole = 24 dm³ at RTP

True for all gases regardless of identity

Formula: Moles from conc. & volume

Moles=Conc×Vol (dm3)\text{Moles} = \text{Conc} \times \text{Vol (dm}^3\text{)}

Unit for concentration in solution calculations

mol/dm³ (or M)

1 dm³ equals how many cm³?

1000 cm³

Formula: Volume from moles & conc.

Vol (dm3)=MolesConc\text{Vol (dm}^3\text{)} = \frac{\text{Moles}}{\text{Conc}}

Key for identifying mole ratios in reactions

Balanced chemical equations

Mole ratio H₂:O₂ in 2H2+O2→2H2O2H_2 + O_2 \rightarrow 2H_2O

2:1

Mole ratio in NaOH+HCl→NaCl+H2ONaOH + HCl \rightarrow NaCl + H_2O

1:1

Join 100,000+ A-Level students studying Flashcards with us.

Select your subjects, and get access to A+ resources today.