suvat in 1D (AQA A-Level Mathematics): Revision Notes
2.3.2 SUVAT in 1D
Kinematics with Constant Acceleration
There are a number of equations of motion:
Where:
- is displacement
- is initial velocity
- is final velocity
- is acceleration
- is time
Example 1:
A particle is moving with an initial velocity equal to 2 ms⁻¹ in a positive direction. Its final velocity after travelling a distance of 20 m is 23 ms⁻¹. Assuming constant acceleration, find the acceleration of the particle.
Given:
- S = 20 m
- U = 2 ms⁻¹
- V = 23 ms⁻¹
- a = ? Using the equation:
Substituting the values:
Simplifying:
Example 2:
A particle is travelling with an initial velocity of 16 ms⁻¹ and over a distance of 350 m, accelerates at a rate of 8 ms⁻². Find the time taken to travel the 350 m journey.
Given:
- S = 350 m
- U = 16 ms⁻¹
- a = 8 ms⁻²
- t = ? Using the equation:
Substituting the values:
Simplifying:
Using the quadratic formula, the time is approximately 7.57 s.
Example: 3
A particle accelerates uniformly. Initially, it has a speed of 6 ms⁻¹, then after 12 seconds, it has a speed of 6 ms⁻¹ in the opposite direction. Find the acceleration of the particle.
Given:
- Using the equation:
Substituting the values:
Simplifying:
Note: A negative acceleration is called deceleration.