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Distance of closest approach of charged particle to nucleus
Zero kinetic energy
V=14πϵ0QrV = \frac{1}{4\pi\epsilon_0}\frac{Q}{r}V=4πϵ01rQ
Eelec=14πϵ0Q1Q2rE_{\text{elec}} = \frac{1}{4\pi\epsilon_0}\frac{Q_1 Q_2}{r}Eelec=4πϵ01rQ1Q2
Electrons are leptons and don't experience strong nuclear force
Around 10−1510^{-15}10−15 m
sinθ=0.61λR\sin\theta = \frac{0.61\lambda}{R}sinθ=R0.61λ
R=kA1/3R = kA^{1/3}R=kA1/3
Approximately 1.45×10171.45 \times 10^{17}1.45×1017 kg/m³
Constant across all nuclei
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