See what we can offer to your school
"SimpleStudy just makes sense...”
Get the best plan for your school
10 questions from this quiz
By calculating closest approach distance
Repulsive electrostatic force
Converts to electric potential energy
Electrons avoid strong nuclear force
Leptons
10−1510^{-15}10−15 m
Concentric circles
sinθ=0.61λR\sin \theta = \frac{0.61 \lambda}{R}sinθ=R0.61λ
R=kA1/3R = kA^{1/3}R=kA1/3
1.45×10171.45 \times 10^{17}1.45×1017 kg/m³
Select your subjects, and get access to A+ resources today.