Fusion (AQA A-Level Physics): Revision Notes
Fusion
Understanding nuclear fusion
Nuclear fusion is the process in which two lighter nuclei combine to form a heavier nucleus. During fusion, energy is released to the surroundings because the product nucleus is more tightly bound than the original lighter nuclei that created it. This increased stability means the nucleus formed has less mass than its constituents, and this mass difference corresponds to the energy released.
The key to understanding fusion lies in binding energy per nucleon - the average energy that holds each nucleon within a nucleus. When lighter nuclei fuse, the resulting nucleus has a higher binding energy per nucleon, indicating greater stability. The difference in binding energy between products and reactants is transferred to the surroundings as released energy.
The relationship between mass and energy in fusion reactions is described by Einstein's famous equation . The "missing" mass after fusion hasn't disappeared - it has been converted into the energy released during the reaction.
Conditions for energy release through fusion
For a fusion process to release energy, a specific condition must be satisfied: the two lighter nuclei undergoing fusion must have lower binding energy per nucleon values than the nucleus they form.
Examining the binding energy per nucleon graph reveals that only nuclei positioned to the left of the peak can satisfy this condition. The peak occurs at iron-56 (Fe), which possesses the highest binding energy per nucleon at approximately MeV/nucleon, making it the most stable nucleus. Therefore, fusion can only release energy when involving nuclei with mass numbers less than 56.
Critical Condition for Energy Release:
Fusion will only release energy if the reactant nuclei are positioned to the left of iron-56 on the binding energy curve. Attempting to fuse nuclei heavier than iron would actually require energy input rather than releasing it.
When lighter nuclei fuse, both the binding energy per nucleon and the nucleon number increase, producing a more stable configuration.
Deuterium-tritium fusion reaction
A frequently studied fusion reaction involves two hydrogen isotopes: deuterium (H) and tritium (H). These isotopes have binding energy per nucleon values of MeV/nucleon and MeV/nucleon respectively. When fused, they produce helium-4 (He) with a significantly higher binding energy per nucleon of MeV/nucleon.
The nuclear reaction equation is:
This reaction also produces a neutron. The substantial increase in binding energy per nucleon when forming helium-4 results in considerable energy transfer to the surroundings, making this reaction particularly useful for potential fusion energy applications.
The deuterium-tritium fusion reaction is favored in experimental fusion reactors because it has the lowest temperature requirement among fusion reactions, occurring at "only" about 100 million kelvin - still incredibly hot, but more achievable than other fusion reactions.
Calculating energy released in fusion
Two equivalent methods exist for determining the energy released during fusion: calculating the change in binding energy or determining the mass defect. Both approaches will yield the same result when applied correctly.
Method 1: Change in binding energy
The energy released equals the difference between total binding energies of products and reactants:
Worked Example: Deuterium-Tritium Fusion Using Binding Energy
For the deuterium-tritium fusion reaction, we calculate the total binding energy for each nucleus:
Products:
- Helium-4:
Reactants:
- Deuterium:
- Tritium:
Calculating energy released:
\text{Change in binding energy} &=& 28.28 - (2.22 + 8.49) \\ &=& 28.28 - 10.71 \\ &=& 17.57 \text{ MeV} \end{array}$$ Therefore, approximately :success[17.6 MeV] is released to the surroundings per fusion reaction.Method 2: Mass defect calculation
Energy release can alternatively be determined through mass loss during the reaction. The mass defect represents the difference between the initial and final masses, which is converted into energy.
Using atomic mass unit values:
- Deuterium nucleus: u
- Tritium nucleus: u
- Helium-4 nucleus: u
- Neutron: u
Worked Example: Deuterium-Tritium Fusion Using Mass Defect
Step 1: Calculate the mass defect
\text{Mass loss} &=& (\text{initial mass}) - (\text{final mass}) \\ &=& (2.01355 + 3.01550) - (4.00150 + 1.00867) \\ &=& 5.02905 - 5.01017 \\ &=& 0.01888 \text{ u} \end{array}$$ **Step 2: Convert mass to energy** Using the conversion factor $931.5$ MeV per atomic mass unit: $$\begin{array}{rcl} \text{Energy released} &=& 0.01888 \times 931.5 \\ &=& 17.59 \text{ MeV} \end{array}$$ Both methods yield :success[equivalent results], confirming approximately :success[17.6 MeV] is released per fusion reaction.Conversion Factor:
The conversion between atomic mass units and energy is MeV/u. This comes from Einstein's mass-energy equivalence and the definition of the atomic mass unit. This conversion factor is essential for all nuclear reaction energy calculations.
Challenges of fusion on Earth
Achieving controlled fusion on Earth faces substantial technical obstacles. Understanding these challenges helps explain why fusion power, despite its immense potential, has not yet been commercially realized.
The primary challenge is overcoming electrostatic repulsion between positively charged nuclei. Since nuclei carry the same positive charge, they naturally repel each other according to Coulomb's law.
The Fusion Challenge:
For fusion to occur, nuclei must approach within approximately m (about one femtometer) so the strong nuclear force can bind them together. This requires overcoming the powerful electrostatic repulsion between the positively charged nuclei.
The solution requires extremely high temperatures - on the order of millions of kelvin - where nuclei possess sufficient kinetic energy to overcome this repulsion.
At these elevated temperatures, nuclei move rapidly enough to collide with sufficient force, allowing the attractive strong nuclear force to overcome the repulsive electrostatic force. The plasma created at these temperatures must also be confined for sufficient time and at sufficient density for fusion reactions to occur at a useful rate.
These extreme temperature requirements present the main engineering challenge for developing practical fusion power generation on Earth. Current experimental reactors like ITER are designed to achieve and maintain these conditions using powerful magnetic fields to confine the superheated plasma.
Fusion in stars
Stars generate their heat and light through fusion reactions occurring in their cores. These natural fusion reactors have been operating for billions of years, providing a model for human attempts at controlled fusion.
Massive stars can fuse nuclei progressively to produce elements as heavy as iron through successive fusion processes. This process, called stellar nucleosynthesis, is responsible for creating most of the elements in the universe.
Temperature in Stellar Cores:
Stellar fusion becomes possible due to the extraordinarily high temperatures in stellar cores - typically 10 to 15 million kelvin in the Sun's core. At these temperatures, nuclei possess enough kinetic energy to move rapidly and overcome mutual electrostatic repulsion. When nuclei collide with sufficient energy, the strong nuclear force dominates, binding them together.
In our Sun, the dominant fusion process converts hydrogen nuclei into helium through a series of reactions known as the proton-proton chain. These stellar fusion reactions constitute the energy source that powers stars, producing the electromagnetic radiation they emit throughout their lifetimes.
The energy released through fusion creates an outward pressure that balances the inward pull of gravity, maintaining the star's stable structure for billions of years.
Key Points to Remember:
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Nuclear fusion combines two lighter nuclei into a heavier nucleus, releasing energy when the product has higher binding energy per nucleon than the reactants
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Only nuclei to the left of iron-56 (Fe) on the binding energy curve can release energy through fusion, as iron-56 has the maximum binding energy per nucleon at approximately MeV/nucleon
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The deuterium-tritium fusion reaction releases approximately 17.6 MeV per reaction and can be calculated using either:
- Binding energy changes: Energy = (total BE of products) - (total BE of reactants)
- Mass defect method: Energy = mass defect × MeV/u
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The conversion factor between atomic mass units and energy is 931.5 MeV/u
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Overcoming electrostatic repulsion between charged nuclei requires extremely high temperatures (millions of kelvin), presenting the main technical challenge for controlled fusion on Earth
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Stars achieve fusion naturally through the immense temperatures and pressures in their cores, where stellar nucleosynthesis creates elements up to iron