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12 questions from this quiz
Energy to raise 1 kg by 1°C
J/kg°C
More thermal energy needed to raise temp
ΔE=m×c×Δθ\Delta E = m \times c \times \Delta\thetaΔE=m×c×Δθ
Change in thermal energy (J)
Change in temperature
4,200 J/kg°C
84,000 J
Ammeter
To minimize heat loss
P=V×IP = V \times IP=V×I
c=ΔEm×Δθc = \frac{\Delta E}{m \times \Delta\theta}c=m×ΔθΔE
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