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10 questions from this quiz
A reduction in speed
Friction or air resistance
F=m⋅ΔvΔtF = \frac{m \cdot \Delta v}{\Delta t}F=Δtm⋅Δv
Newtons
Requires more force
7,200 N
Faster needs greater force
Reduce friction, harder to decelerate
Greater decelerating forces required
Friction between tyres and road
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