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12 questions from this quiz
Reducing concentration by adding solvent
The amount of solute
12 M
Vol1×M1=Vol2×M2\text{Vol}_1 \times M_1 = \text{Vol}_2 \times M_2Vol1×M1=Vol2×M2
The concentration of the solution
Step-by-step dilution by same factor
1:10
125 cm³
Total volumeStock volume\frac{\text{Total volume}}{\text{Stock volume}}Stock volumeTotal volume
1000
Final is always lower
0.1 M
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