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10 questions from this quiz
Points equidistant from a centre
Centre of the circle
Radius of the circle
(x−3)2+(y+2)2=25(x - 3)^2 + (y + 2)^2 = 25(x−3)2+(y+2)2=25
(4,−1)(4, -1)(4,−1)
444
(x−h)2+(y−k)2=r2(x - h)^2 + (y - k)^2 = r^2(x−h)2+(y−k)2=r2
Substitute coordinates into equation
Yes, because 32+42=253^2 + 4^2 = 2532+42=25
Fixed distance from centre to circle
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