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12 cards from this deck
Collisions at angles, not head-on
Momentum is conserved
Applied separately to x and y directions
vx=vcosθv_x = v \cos θvx=vcosθ
vy=vsinθv_y = v \sin θvy=vsinθ
v=vx2+vy2v = \sqrt{v_x^2 + v_y^2}v=vx2+vy2
tanθ=vyvx\tan θ = \frac{v_y}{v_x}tanθ=vxvy
Eject mass, gain momentum in opposite direction
F=dpdtF = \frac{dp}{dt}F=dtdp
Both momentum and kinetic energy
Only momentum, not kinetic energy
Momentum is a vector quantity
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