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10 cards from this deck
p⃗=mv⃗\vec{p} = m\vec{v}p=mv
kg⋅m⋅s−1\text{kg} \cdot \text{m} \cdot \text{s}^{-1}kg⋅m⋅s−1
Vector
Same as velocity direction
F⃗net=Δp⃗Δt\vec{F}_{\text{net}} = \frac{\Delta \vec{p}}{\Delta t}Fnet=ΔtΔp
Total momentum in isolated system is constant
∑p⃗initial=∑p⃗final\sum \vec{p}_{\text{initial}} = \sum \vec{p}_{\text{final}}∑pinitial=∑pfinal
Δp⃗A=−Δp⃗B\Delta \vec{p}_A = -\Delta \vec{p}_BΔpA=−ΔpB
Apply separately in x and y directions
Not converting mass to kg
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