Applications of the Uniform Circular Motion Model (HSC SSCE Physics): Quizzes

Only tension along its length

Horizontal component $F_T \cos\theta$

$v = \frac{2\pi r}{T}$

Tension is greater than $mg$

Both magnitude and direction vary

Friction force on the tyres

Increases with square of velocity

Four times as much

Horizontal component of normal force

Speed and radius only