Calculations Involving Equilibrium (VCE SSCE Chemistry): Quizzes

It becomes the reciprocal: $1/K$

It is squared: $(K_{\text{original}})^2$

Products dominate at equilibrium

Very little reaction occurs

Intermediate (appreciable amounts of both)

$K$ for CO binding is ~20,000 times larger

Equilibrium concentrations only

Weak acid (only partially dissociates)

Initial, Change, Equilibrium

Rearrange the equilibrium expression