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10 cards from this deck
Multiplying their arguments
Dividing their arguments
f(xy)f(xy)f(xy)
f(x)f(y)f(x)f(y)f(x)f(y)
Multiplying exponential values
Yes, for all values of xxx and yyy
No, the constant term prevents this
(x+y)f(xy)(x + y)f(xy)(x+y)f(xy)
Find one counterexample
f(x)=1xf(x) = \frac{1}{x}f(x)=x1 is undefined at x=0x = 0x=0
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