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10 questions from this quiz
Apply fff first, then apply ggg
Range of fff must be in domain of ggg
f(x)=x2f(x) = x^2f(x)=x2 and g(x)=exg(x) = e^xg(x)=ex
It must be one-to-one
Domain of f−1f^{-1}f−1 equals range of fff
Whenever a>ba > ba>b, we have f(a)>f(b)f(a) > f(b)f(a)>f(b)
Whenever a>ba > ba>b, we have f(a)<f(b)f(a) < f(b)f(a)<f(b)
Yes, they are always one-to-one
f−1f^{-1}f−1 is strictly increasing
g−1(x)=1x2g^{-1}(x) = \frac{1}{x^2}g−1(x)=x21
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