Circular Motion (VCE SSCE Physics): Flashcards

Constant speed, continuously changing direction

Center-seeking

Toward the center of the circular path

$a_c = \frac{v^2}{r}$

$F_c = \frac{mv^2}{r}$

Four (force increases with square of velocity)

Tangent to the circle (perpendicular to radius)

At the bottom

$v = \sqrt{rg \tan\theta}$

No, mass cancels out