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10 questions from this quiz
It remains so unless unbalanced force acts
Only its mass
Vector sum of all forces
mgcosθmg \cos \thetamgcosθ
On different bodies
N=m(avertical+g)N = m(a_{vertical} + g)N=m(avertical+g)
Backward (opposite to velocity)
Only gravity acts on the object
They both act on the same body
Add all masses: a=Fnet/(m1+m2+...)a = F_{net}/(m_1+m_2+...)a=Fnet/(m1+m2+...)
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