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15 cards from this deck
Moles of solute per litre of solution
M=molesvolume (L)M = \frac{\text{moles}}{\text{volume (L)}}M=volume (L)moles
M=g/Lmolecular massM = \frac{\text{g/L}}{\text{molecular mass}}M=molecular massg/L
g/L=M×molecular mass\text{g/L} = M \times \text{molecular mass}g/L=M×molecular mass
moles=V(cm³)×M1000\text{moles} = \frac{\text{V(cm³)} \times M}{1000}moles=1000V(cm³)×M
V(cm³)=moles×1000M\text{V(cm³)} = \frac{\text{moles} \times 1000}{M}V(cm³)=Mmoles×1000
1000 cm³
moles=massmolecular mass\text{moles} = \frac{\text{mass}}{\text{molecular mass}}moles=molecular massmass
Using basic definitions to break down problems
Stays the same
Balanced equation, molarity, volume, molar ratios
Inverse: smaller volume = higher concentration
40 g/mol
Determines how much product forms
Molarity (M)
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