Answering Questions about Solutions (Leaving Cert Chemistry): Quizzes

Moles of solute per litre of solution

Molarity = mass in g/L $\div$ molecular mass

Mass (g/L) = Molarity $\times$ Molecular mass

$0.092$ M

Moles = (Volume in $\text{cm}^3$ $\times$ Molarity) $\div$ $1000$

Volume ($\text{cm}^3$) = (Moles $\times$ $1000$) $\div$ Molarity

$1000$ $\text{cm}^3$

Concentration remains the same

Moles decrease proportionally

Moles = Mass $\div$ Molecular mass

Calculate moles of solution reactant

Moles per $1000$ $\text{cm}^3$ ($1$ litre)