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10 cards from this deck
Line touching curve at one point with same slope as curve
Derivative gives gradient of tangent at that point
yβy1=fβ²(x1)(xβx1)y - y_1 = f'(x_1)(x - x_1)yβy1β=fβ²(x1β)(xβx1β)
Line perpendicular to tangent at a point on curve
Product of gradients equals β1-1β1: m1m2=β1m_1 m_2 = -1m1βm2β=β1
β1m-\frac{1}{m}βm1β (negative reciprocal)
Point (x1,y1)(x_1, y_1)(x1β,y1β) on curve and derivative fβ²(x1)f'(x_1)fβ²(x1β)
Function continuous and fβ²(x)ββf'(x) \to \inftyfβ²(x)ββ at that point
fβ²(x)ββf'(x) \to \inftyfβ²(x)ββ from one side, ββ-\inftyββ from other
Flip and flip the sign (reciprocal then negate)
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