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10 cards from this deck
Probability distribution of a sample statistic
n!x!(n−x)!\frac{n!}{x!(n-x)!}x!(n−x)!n!
P^=Xn\hat{P} = \frac{X}{n}P^=nX
ppp
p(1−p)n\sqrt{\frac{p(1-p)}{n}}np(1−p)
Standard deviation of a sample statistic
Sample proportion (as a random variable)
Yes, E(P^)=pE(\hat{P}) = pE(P^)=p
Standard deviation decreases
Probability of attribute remains constant for each selection
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