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10 questions from this quiz
Distribution of a sample statistic
E(P^)=pE(\hat{P}) = pE(P^)=p
sd(P^)=p(1−p)n\text{sd}(\hat{P}) = \sqrt{\frac{p(1-p)}{n}}sd(P^)=np(1−p)
(nx)=n!x!(n−x)!\binom{n}{x} = \frac{n!}{x!(n-x)!}(xn)=x!(n−x)!n!
P^=Xn\hat{P} = \frac{X}{n}P^=nX where XXX is binomial
The standard deviation of a sample stat
It decreases
p=0.6p = 0.6p=0.6
Probability remains constant for each sel
(42)0.720.32\binom{4}{2}0.7^2 0.3^2(24)0.720.32
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