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10 questions from this quiz
Probability distribution
μ\muμ or E(X)E(X)E(X)
∑xx⋅p(x)\sum_{x} x \cdot p(x)∑xx⋅p(x)
No, they are generally not equal
aE(X)+baE(X) + baE(X)+b
Spread around the mean
E(X2)−[E(X)]2E(X^2) - [E(X)]^2E(X2)−[E(X)]2
sd(X)=Var(X)sd(X) = \sqrt{Var(X)}sd(X)=Var(X)
a2Var(X)a^2Var(X)a2Var(X)
Variance stays the same
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