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y=ax2+bx+cdx2+ex+fy = \frac{ax^2 + bx + c}{dx^2 + ex + f}y=dx2+ex+fax2+bx+c
Intercepts → Asymptotes → Range → Turning points
Substitute x=0x = 0x=0 into equation
Set y=0y = 0y=0, solve numerator = 0
Set denominator = 0 and solve
y=ady = \frac{a}{d}y=da (ratio of leading coefficients)
Yes, at specific finite x-values
Rearrange as quadratic in x, apply discriminant ≥0\geq 0≥0
At boundary values of the range
When numerator = 0 (and denominator ≠0\neq 0=0)
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