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10 questions from this quiz
Prove statements for all natural numbers
Base case, inductive step, conclusion
Assuming the statement is true for n=kn = kn=k
The statement is true for n=1n = 1n=1
True for n=k+1n = k + 1n=k+1 using n=kn = kn=k
Write expression as multiple of divisor
Missing the base case
Mathematical induction
∑r=1k+(k+1)\sum_{r=1}^{k} + (k+1)∑r=1k+(k+1)th term
Look for common factors first
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