Solving trigonometry problems (Edexcel GCSE Maths): Revision Notes
Solving trigonometry problems
Understanding exact trigonometry values is essential for solving problems without a calculator. These special values appear frequently in GCSE exams, particularly in non-calculator papers.
Exact trigonometry values are crucial for GCSE success because they allow you to solve trigonometry problems precisely without relying on decimal approximations from a calculator. Mastering these values will significantly improve your problem-solving speed and accuracy.
What are exact trigonometry values?
Exact trigonometry values are the precise sin, cos and tan values for specific angles that can be expressed as fractions or surds, rather than decimal approximations.
You need to memorise these values as they often appear in exam questions where calculators are not permitted. Learning these values will help you solve trigonometry problems quickly and accurately.
Special angle values
The 30-60-90 triangle
This right-angled triangle provides exact values for 30° and 60° angles:
For 30°:
For 60°:
The triangle has sides in the ratio 1 : √3 : 2, which helps you remember these relationships.
The 45-45-90 triangle
This isosceles right-angled triangle gives exact values for 45° angles:
Since this is an isosceles triangle, the two shorter sides are equal, making sin and cos values identical.
Edge case values
You must also know these boundary values:
For 0°:
For 90°:
tan 90° is undefined - entering this into a calculator gives an error. This is a common source of mistakes in exams, so always remember that tangent is undefined at 90°.
Using exact values in calculations
When solving triangles using exact values, apply the standard trigonometry formulas:
Finding side lengths
Worked Example: Finding Side Length
Triangle ABC has a right angle at B. Angle BAC = 60° and AC = 14 cm. Calculate the length of AB.
Solution: Using :
Answer: AB = 7 cm
Pattern and arrangement problems
Some questions involve arranging identical shapes to create patterns.
Worked Example: Pattern Arrangement
Amy arranges identical triangles around a point to make a pattern. Each triangle has angles of 30°, 60° and 90°. Show that she can fit exactly 12 triangles around a point.
Solution: Using the triangle:
Therefore x° = 30°
Since there are 360° around a point:
Conclusion: Amy can fit exactly 12 triangles around the point.
Exam tips
Essential Exam Strategies:
- Always sketch the triangle before solving when the problem describes one
- For non-calculator questions, you must use exact values - decimal approximations won't earn marks
- Write a clear conclusion explaining how your working leads to the answer
- Learn these values by heart - they appear regularly in exams
Practice problem
Practice Challenge:
A vertical flagpole AB is supported with a wire AC at an angle of 60° to the ground. The base of the wire is 2.4 m from the base of the flagpole. Show that the length of the wire AC is 4.8 m.
Hint: Use and the given measurements to find the hypotenuse.
Key takeaways
Key Points to Remember:
- Memorise exact values for 0°, 30°, 45°, 60° and 90°
- Use these values in non-calculator questions only
- Sketch triangles when problems describe them to help visualise the solution
- Remember that tan 90° is undefined and will cause calculator errors
- Always show your complete working and write a clear conclusion