Continuous Distributions (HSC SSCE Mathematics Advanced): Flashcards

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Continuous distributions
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P(X=h)P(X = h) for any specific value in continuous dist.

Exactly zero

How probabilities calculated in continuous dists.

Over intervals, not single points

CDF F(x)F(x) represents

P(Xx)P(X \leq x)

Relationship: PDF to CDF

f(x)=F(x)f(x) = F'(x) (PDF is derivative of CDF)

Two properties for valid PDF

f(x)0f(x) \geq 0 and abf(x)dx=1\int_a^b f(x)dx = 1

Calculate P(hXk)P(h \leq X \leq k) using PDF

hkf(x)dx\int_h^k f(x)dx (area under curve)

CDF values at endpoints aa and bb

F(a)=0F(a) = 0, F(b)=1F(b) = 1

Uniform distribution PDF on [a,b][a,b]

f(x)=1baf(x) = \frac{1}{b-a}

Finding median using CDF

Set F(x)=12F(x) = \frac{1}{2}, solve for xx

\leq vs << in continuous probability intervals

No difference (same probability)

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