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10 cards from this deck
Total area covering all outer surfaces of a 3D object
SA=2πrhSA = 2\pi rhSA=2πrh
SA=2πr2+2πrhSA = 2\pi r^2 + 2\pi rhSA=2πr2+2πrh
Divide diameter by 2
SA=4πr2SA = 4\pi r^2SA=4πr2
SA=2πr2SA = 2\pi r^2SA=2πr2
SA=3πr2SA = 3\pi r^2SA=3πr2
Only the curved surface, no top or bottom circles
Open hemisphere SA is exactly half of sphere SA
Curved surface (2πr22\pi r^22πr2) + circular base (πr2\pi r^2πr2)
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