See what we can offer to your school
"SimpleStudy just makes sense...”
Get the best plan for your school
10 cards from this deck
Relates InI_nIn to In−1I_{n-1}In−1 and/or In−2I_{n-2}In−2
∫udvdxdx=uv−∫vdudxdx\int u \frac{dv}{dx} dx = uv - \int v \frac{du}{dx} dx∫udxdvdx=uv−∫vdxdudx
Avoid repeated integration by parts; derive formula once
Recursive relationship
Part containing power nnn so power reduces when differentiated
Both definite and indefinite integrals
In=−nIn−1I_n = -nI_{n-1}In=−nIn−1
In=n−1nIn−2I_n = \frac{n-1}{n}I_{n-2}In=nn−1In−2
Reach I0I_0I0 or I1I_1I1, evaluate directly, substitute back
Even powers reduce to I0I_0I0, odd powers to I1I_1I1
Select your subjects, and get access to A+ resources today.