Reduction Formulae (AQA A-Level Further Maths): Quizzes

Integrals with lower indices like $I_{n-1}$

$\int u \frac{dv}{dx} dx = uv - \int v \frac{du}{dx} dx$

They avoid repeated manual integration

As the part containing power $n$

$I_n = -nI_{n-1}$

$I_{n-2}$

$I_0$

Yes, for both definite and indefinite

As $\sin x \cdot \sin^{n-1} x$

$I_0$ or $I_1$