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10 questions from this quiz
Length when no forces act on it
T=λlxT = \frac{\lambda}{l}xT=lλx
0.5 m
Newtons (N)
EPE=λ2lx2\text{EPE} = \frac{\lambda}{2l}x^2EPE=2lλx2
5 N m−1^{-1}−1
They have negligible mass (light)
The tensions in both strings are equal
0.5 J
Loss in EPE
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