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x=−b±b2−4ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}x=2a−b±b2−4ac
ax2+bx+c=0ax^2 + bx + c = 0ax2+bx+c=0
Gives two solutions (one with +, one with -)
b2−4acb^2 - 4acb2−4ac
2a2a2a (not just aaa)
Minus signs
Roots
Won't factorise easily or need decimals/surds/exact answers
Rearrange into standard form ax2+bx+c=0ax^2 + bx + c = 0ax2+bx+c=0
Coefficients
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