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12 cards from this deck
Extension of 2D Pythagoras to three dimensions
Longest line through 3D shape interior, corner to opposite corner
a2+b2+c2=d2a^2 + b^2 + c^2 = d^2a2+b2+c2=d2
Three perpendicular edges of the cuboid
Space diagonal from corner to opposite corner
2D Pythagoras applied twice in succession
Find base diagonal: e2=a2+b2e^2 = a^2 + b^2e2=a2+b2
Use diagonal & height: d2=e2+c2d^2 = e^2 + c^2d2=e2+c2
All dimensions equal, only need one measurement
Can be adapted to solve problems with pyramids and other 3D shapes
Identify the shape
Find the three perpendicular dimensions
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