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10 questions from this quiz
P(A and B)=P(A)×P(B)P(A \text{ and } B) = P(A) \times P(B)P(A and B)=P(A)×P(B)
Yes, replacement keeps composition unchanged
14\frac{1}{4}41
518\frac{5}{18}185
Yes, 0.12 = 0.3 × 0.4
Check if P(A and B)=0P(A \text{ and } B) = 0P(A and B)=0
No, they are completely different concepts
It changes to focus on outcomes in B
Dependent events
Events are dependent
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